Filename from path

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    Giovanny Gongora

    Codiga's C++ Recipes

    Get a file name from a Windows path

    #include <string>
    
    int main() {
      std::string filename = "C:\\MyDirectory\\MyFile.bat";
      const size_t last_slash_idx = filename.find_last_of("\\/");
      if (std::string::npos != last_slash_idx) {
        filename.erase(0, last_slash_idx + 1);
      }
      const size_t period_idx = filename.rfind('.');
      if (std::string::npos != period_idx) {
        filename.erase(period_idx);
      }
      return 0;
    }
    
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