Function

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    0

    lucycodes42

    Haskell public recipes

    The expression ${name} ${val} is equivalent to name val. The expressions ${name} ${val2:_} are equivalent to name val2.

    Shortcut: fun

    ${name} :: ${type1:Int} -> ${type2:Int}
    ${name} ${val} = ${expr1}
    ${name} ${val2:_} = ${expr2}
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