void leftRotatebyOne(int arr[], int n){
int temp = arr[0];
for (int i = 0; i < n - 1; i++)
arr[i] = arr[i + 1];
arr[n-1] = temp;
}
Left Rotate Array by one
This code is a loop that rotates the array by one spot to the left. The temp variable stores the current position of the array after the loop.
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